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3.5 Trigonometry (A-level only)

3.5 Trigonometry (A-level only)

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Question 138
i.

Show that

1tan⁡θ−tan⁡θ≡cos⁡2θsin⁡θcos⁡θ \frac{1}{\tan \theta} - \tan \theta \equiv \frac{\cos 2\theta}{\sin \theta \cos \theta} tanθ1​−tanθ≡sinθcosθcos2θ​

for θ≠nπ2\theta \neq \frac{n\pi}{2}θ=2nπ​ where n∈Zn \in \mathbb{Z}n∈Z.

[3]
ii.

Solve, for 0∘≤x<90∘0^\circ \le x < 90^\circ0∘≤x<90∘, the equation

5sin⁡2(2x−15∘)=2 5 \sin^2(2x - 15^\circ) = 2 5sin2(2x−15∘)=2

giving your answers in degrees to one decimal place. (Solutions based entirely on graphical or numerical methods are not acceptable.)

[6]
Markscheme

3.5 Trigonometry (A-level only) Questions

  1. A Level
  2. /Maths
  3. /3.5 Trigonometry (A-level only)

225 exam-style questions on WJEC A Level Maths 3.5 Trigonometry (A-level only), covering 3.5.1 Trigonometry (A-level only), 3.5.2 Trigonometry (A-level only), 3.5.3 Trigonometry (A-level only), 3.5.4 Trigonometry (A-level only), 3.5.5 Trigonometry (A-level only), 3.5.6 Trigonometry (A-level only), 3.5.7 Trigonometry (A-level only), and 3.5.8 Trigonometry (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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