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1.9.27 Integration by substitution (reverse chain rule) (A-level only)

1.9.27 Integration by substitution (reverse chain rule) (A-level only)

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Question 17
i.

Find

∫24(2x+5)2 dx \int \frac{24}{(2x + 5)^2} \, dx ∫(2x+5)224​dx

giving your answer in simplest form.

[2]
ii a.

Write 5x+3x+4\frac{5x + 3}{x + 4}x+45x+3​ in the form

A+Bx+4 where A and B are constants to be found A + \frac{B}{x + 4} \text{ where } A \text{ and } B \text{ are constants to be found} A+x+4B​ where A and B are constants to be found
[2]
ii b.

Hence find, using algebraic integration, the exact value of

∫−9−55x+3x+4 dx \int_{-9}^{-5} \frac{5x + 3}{x + 4} \, dx ∫−9−5​x+45x+3​dx

giving your answer in simplest form.

[3]
Markscheme

1.9.27 Integration by substitution (reverse chain rule) (A-level only) Questions

  1. A Level
  2. /Maths
  3. /1.9.27 Integration by substitution (reverse chain rule) (A-level only)

36 exam-style questions on OCR (MEI) A Level Maths 1.9.27 Integration by substitution (reverse chain rule) (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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