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1.9.27 Integration by substitution (reverse chain rule) (A-level only)
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Question 12
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Find:
∫1224(2x+1)3dx\displaystyle \int_1^2 \frac{24}{(2x + 1)^3} dx
∫
1
2
(
2
x
+
1
)
3
24
d
x
[5]
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1.9.27 Integration by substitution (reverse chain rule) (A-level only) Questions
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1.9.27 Integration by substitution (reverse chain rule) (A-level only)
