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1.9.27 Integration by substitution (reverse chain rule) (A-level only)

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Question 14

Find: ∫0110(2x+1)3dx\displaystyle \int_0^1 \frac{10}{(2x + 1)^3} dx∫01​(2x+1)310​dx

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1.9.27 Integration by substitution (reverse chain rule) (A-level only) Questions

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  3. /1.9.27 Integration by substitution (reverse chain rule) (A-level only)