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1.9.27 Integration by substitution (reverse chain rule) (A-level only)

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Question 11

Integrate with respect to xxx:

a.

(4x+3)2(4x + 3)^2(4x+3)2

[3]
b.

1(3x−2)5\displaystyle \frac{1}{(3x - 2)^5}(3x−2)51​

[3]

1.9.27 Integration by substitution (reverse chain rule) (A-level only) Questions

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