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1.9.27 Integration by substitution (reverse chain rule) (A-level only)

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Question 10

Find: ∫2543x+21dx\displaystyle \int_2^5 \frac{4}{3x + 21} dx∫25​3x+214​dx

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1.9.27 Integration by substitution (reverse chain rule) (A-level only) Questions

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  3. /1.9.27 Integration by substitution (reverse chain rule) (A-level only)