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1.9.27 Integration by substitution (reverse chain rule) (A-level only)
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Question 10
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Find:
∫2543x+21dx\displaystyle \int_2^5 \frac{4}{3x + 21} dx
∫
2
5
3
x
+
21
4
d
x
[5]
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1.9.27 Integration by substitution (reverse chain rule) (A-level only) Questions
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1.9.27 Integration by substitution (reverse chain rule) (A-level only)