The volume V m3V \text{ m}^3V m3 of a spherical weather balloon with radius r mr \text{ m}r m is given by the formula
V=43πr3 V = \frac{4}{3}\pi r^3 V=34πr3Find dVdr\frac{dV}{dr}drdV giving your answer in simplest form.
At time ttt seconds, helium is being pumped into the balloon such that the volume is increasing according to the differential equation
dVdt=1600(4t+2)2,t≥0 \frac{dV}{dt} = \frac{1600}{(4t + 2)^2}, \quad t \ge 0 dtdV=(4t+2)21600,t≥0Given that V=0V = 0V=0 when t=0t = 0t=0:
(i) Solve this differential equation to show that
V=400t2t+1 V = \frac{400t}{2t + 1} V=2t+1400t(ii) Hence find the upper limit to the volume of the balloon.
Find the radius of the balloon at t=4.5t = 4.5t=4.5, giving your answer in m to 3 significant figures.
Find the rate of increase of the radius of the balloon at t=4.5t = 4.5t=4.5, giving your answer to 2 significant figures. Show your working and state the units of your answer.
425 exam-style questions on OCR A Level Maths 1.7 Differentiation, covering 1.7.1 Derivative as gradient of the tangent, 1.7.2 Gradient of the tangent at a point, 1.7.3 Sketching the gradient function, 1.7.4 Second derivatives, 1.7.5 Second derivative as rate of change of gradient, 1.7.6 Convex, concave and points of inflection (A-level only), 1.7.7 Differentiation from first principles for powers of x, 1.7.8 Differentiation from first principles for sin x and cos x (A-level only), 1.7.9 Differentiating x^n, 1.7.10 Differentiating e^(kx) and a^(kx) (A-level only), 1.7.11 Differentiating trigonometric functions (A-level only), 1.7.12 Derivative of ln x (A-level only), 1.7.13 Tangents and normals, 1.7.14 Stationary points, 1.7.15 Increasing and decreasing functions, 1.7.16 Points of inflection (A-level only), 1.7.17 Product and quotient rules (A-level only), 1.7.18 Chain rule (A-level only), 1.7.19 Parametric and implicit differentiation (A-level only), 1.7.20 Constructing differential equations (A-level only), and 1.7 Differentiation. Each one has a worked solution and a mark scheme showing where the marks go.