Show that the equation 3sin2xtan2x=cos2x+23\sin 2x \tan 2x = \cos 2x + 23sin2xtan2x=cos2x+2 can be written in the form 4cos22x+2cos2x−3=04\cos^2 2x + 2\cos 2x - 3 = 04cos22x+2cos2x−3=0
Find all values for x x\,x in the interval 0≤x<180∘0 \leq x < 180^\circ0≤x<180∘, for which 3sin2xtan2x=cos2x+23\sin 2x \tan 2x = \cos 2x + 23sin2xtan2x=cos2x+2. Give your answers to two decimal places.
41 exam-style questions on Edexcel A Level Maths Trigonometric Identities and Equations, covering 10.1 Angles in all four Quadrants, 10.2 Exact Values of Trigonometric Ratios, 10.3 Trigonometric Identities, 10.4 Solving Trigonometric Equations, 10.5 Harder Trigonometric Equations, and 10.6 Equations and Identities. Each one has a worked solution and a mark scheme showing where the marks go.