Show that
2cos2x+sinx−2=0 2\cos^2 x + \sin x - 2 = 0 2cos2x+sinx−2=0can be written as
sinx(2sinx−1)=0 \sin x(2\sin x - 1) = 0 sinx(2sinx−1)=0Hence find all solutions of
2cos2x+sinx−2=0 2\cos^2 x + \sin x - 2 = 0 2cos2x+sinx−2=0where 0∘≤x<360∘ 0^\circ \leq x < 360^\circ\,0∘≤x<360∘
Give your solutions to the nearest degree.
322 exam-style questions on Edexcel A Level Maths Trigonometric Identities and Equations, covering 10.1 Angles in all four Quadrants, 10.2 Exact Values of Trigonometric Ratios, 10.3 Trigonometric Identities, 10.4 Solving Trigonometric Equations, 10.5 Harder Trigonometric Equations, and 10.6 Equations and Identities. Each one has a worked solution and a mark scheme showing where the marks go.