Show that the equation
6cos2x=4−sinx 6\cos^2 x = 4 - \sin x 6cos2x=4−sinxcan be written in the form
6sin2x−sinx−2=0 6\sin^2 x - \sin x - 2 = 0 6sin2x−sinx−2=0Hence solve, for 0≤x<360∘0 \leq x < 360^\circ0≤x<360∘, the equation
6cos2x=4−sinx 6\cos^2 x = 4 - \sin x 6cos2x=4−sinxGive your answers to one decimal place where appropriate.
41 exam-style questions on Edexcel A Level Maths Trigonometric Identities and Equations, covering 10.1 Angles in all four Quadrants, 10.2 Exact Values of Trigonometric Ratios, 10.3 Trigonometric Identities, 10.4 Solving Trigonometric Equations, 10.5 Harder Trigonometric Equations, and 10.6 Equations and Identities. Each one has a worked solution and a mark scheme showing where the marks go.