The diagram shows parts of the curves y=8cos2θy = 8\cos^2\thetay=8cos2θ and y=7−2tanθcosθy = 7 - 2\tan\theta \cos\thetay=7−2tanθcosθ, where θ \theta\,θ is in degrees.
Show that the equation 7−2tanθcosθ=8cos2θ7 - 2\tan\theta \cos\theta = 8\cos^2\theta7−2tanθcosθ=8cos2θ can be expressed in the form 8sin2x−2sinx−1=08\sin^2 x - 2\sin x - 1 = 08sin2x−2sinx−1=0
Solve the inequality 7−2tanθcosθ>8cos2θ7 - 2\tan\theta \cos\theta > 8\cos^2\theta7−2tanθcosθ>8cos2θ for 0∘≤θ<360∘0^\circ \leq \theta < 360^\circ0∘≤θ<360∘
322 exam-style questions on Edexcel A Level Maths Trigonometric Identities and Equations, covering 10.1 Angles in all four Quadrants, 10.2 Exact Values of Trigonometric Ratios, 10.3 Trigonometric Identities, 10.4 Solving Trigonometric Equations, 10.5 Harder Trigonometric Equations, and 10.6 Equations and Identities. Each one has a worked solution and a mark scheme showing where the marks go.