Show that 3−3cos4x3+3cos4x≡tan22x\displaystyle \frac{3 - 3\cos 4x}{3 + 3\cos 4x} \equiv \tan^2 2x3+3cos4x3−3cos4x≡tan22x
Hence solve, for −π≤x≤π-\pi \leq x \leq \pi−π≤x≤π,
3−3cos4x3+3cos4x=13 \frac{3 - 3\cos 4x}{3 + 3\cos 4x} = \frac{1}{3} 3+3cos4x3−3cos4x=31348 exam-style questions on Edexcel A Level Maths Trigonometry and Modelling, covering 7.1 Addition Formulae, 7.2 Double Angle Formulae, 7.3 Solving Trigonometric Equations, 7.4 Simplifying a cos x +- b sin x, 7.5 Proving Trigonometric Identities, and 7.6 Modelling with Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.