Prove the identity:
cos2xsin2x≡1−tan2x2tanx \frac{\cos 2x}{\sin 2x} \equiv \frac{1-\tan^2 x}{2\tan x} sin2xcos2x≡2tanx1−tan2xHence, solve, for 0≤θ<2π0 \leq \theta < 2\pi0≤θ<2π,
cos2θ=0 \cos 2\theta = 0 cos2θ=0348 exam-style questions on Edexcel A Level Maths Trigonometry and Modelling, covering 7.1 Addition Formulae, 7.2 Double Angle Formulae, 7.3 Solving Trigonometric Equations, 7.4 Simplifying a cos x +- b sin x, 7.5 Proving Trigonometric Identities, and 7.6 Modelling with Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.