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Trigonometry and Modelling

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Question 156
a.

Show that 1−cos⁡2x1+cos⁡2x≡tan⁡2x\displaystyle \frac{1 - \cos 2x}{1 + \cos 2x} \equiv \tan^2 x1+cos2x1−cos2x​≡tan2x

[4]
b.

Hence solve, for −π≤x≤π-\pi \leq x \leq \pi−π≤x≤π, where k>0k>0k>0,

1−cos⁡2x1+cos⁡2x=k \frac{1 - \cos 2x}{1 + \cos 2x} = k 1+cos2x1−cos2x​=k
[2]
Markscheme

Trigonometry and Modelling Questions

  1. A Level
  2. /Maths
  3. /Trigonometry and Modelling

348 exam-style questions on Edexcel A Level Maths Trigonometry and Modelling, covering 7.1 Addition Formulae, 7.2 Double Angle Formulae, 7.3 Solving Trigonometric Equations, 7.4 Simplifying a cos x +- b sin x, 7.5 Proving Trigonometric Identities, and 7.6 Modelling with Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.

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