Show that
3sin3x≡9sinx−12sin3x 3\sin 3x \equiv 9\sin x - 12\sin^3 x 3sin3x≡9sinx−12sin3xHence, solve, for 0≤x<π0 \leq x < \pi0≤x<π,
12sin3x−9sinx=0 12 \sin^3 x - 9 \sin x = 0 12sin3x−9sinx=0348 exam-style questions on Edexcel A Level Maths Trigonometry and Modelling, covering 7.1 Addition Formulae, 7.2 Double Angle Formulae, 7.3 Solving Trigonometric Equations, 7.4 Simplifying a cos x +- b sin x, 7.5 Proving Trigonometric Identities, and 7.6 Modelling with Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.