Given that sinθ≠±1\sin \theta \neq \pm 1sinθ=±1, prove the identity
11−sinθ+11+sinθ≡2sec2θ \frac{1}{1 - \sin \theta} + \frac{1}{1 + \sin \theta} \equiv 2 \sec^2 \theta 1−sinθ1+1+sinθ1≡2sec2θHence, find the set of values of kkk for which the equation
11−sinθ+11+sinθ=k \frac{1}{1 - \sin \theta} + \frac{1}{1 + \sin \theta} = k 1−sinθ1+1+sinθ1=khas real solutions. Fully justify your answer.
Given that θ\thetaθ is in the second quadrant (reflex angle between 90∘90^\circ90∘ and 180∘180^\circ180∘) and
11−sinθ+11+sinθ=10 \frac{1}{1 - \sin \theta} + \frac{1}{1 + \sin \theta} = 10 1−sinθ1+1+sinθ1=10find the exact value of tanθ\tan \thetatanθ.
137 exam-style questions on Edexcel A Level Maths Trigonometry and Modelling, covering 7.1 Addition Formulae, 7.2 Double Angle Formulae, 7.3 Solving Trigonometric Equations, 7.4 Simplifying a cos x +- b sin x, 7.5 Proving Trigonometric Identities, and 7.6 Modelling with Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.