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Trigonometric Functions

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Question 146
a.

Prove that csc⁡θcsc⁡θ−sin⁡θ≡sec⁡2θ\displaystyle \frac{\csc \theta}{\csc \theta - \sin \theta} \equiv \sec^2 \thetacscθ−sinθcscθ​≡sec2θ

[4]
b.

Hence solve, for 0<θ<2π0 < \theta < 2\pi0<θ<2π, csc⁡θcsc⁡θ−sin⁡θ=2tan⁡θ\displaystyle \frac{\csc \theta}{\csc \theta - \sin \theta} = 2 \tan \thetacscθ−sinθcscθ​=2tanθ, and hence find the exact value of the sum of the solutions.

[4]
Markscheme

Trigonometric Functions Questions

  1. A Level
  2. /Maths
  3. /Trigonometric Functions

274 exam-style questions on Edexcel A Level Maths Trigonometric Functions, covering 6.1 Secant, Cosecant and Cotangent, 6.2 Graphs of Sec x, Cosec x and Cot x, 6.3 Using Sec x, Cosec x and Cot x, 6.4 Trigonometric Identities, and 6.5 Inverse Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.

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