Prove that: sec6x−tan6x≡1+3tan2x+3tan4x\sec^6x - \tan^6x \equiv 1 + 3 \tan^2x + 3 \tan^4xsec6x−tan6x≡1+3tan2x+3tan4x
Hence solve, for 0∘≤x≤360∘0^\circ \leq x \leq 360^\circ0∘≤x≤360∘, the equation,
sec6x−tan6x=7 \sec^6x - \tan^6x = 7 sec6x−tan6x=7274 exam-style questions on Edexcel A Level Maths Trigonometric Functions, covering 6.1 Secant, Cosecant and Cotangent, 6.2 Graphs of Sec x, Cosec x and Cot x, 6.3 Using Sec x, Cosec x and Cot x, 6.4 Trigonometric Identities, and 6.5 Inverse Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.