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Trigonometric Functions

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Question 187

The equation 2sec⁡2x+4tan⁡2x=−5sec⁡x2 \sec^2 x + 4 \tan^2 x = -5 \sec x2sec2x+4tan2x=−5secx can be written in the form 6sec⁡2x+5sec⁡x−4=06 \sec^2 x + 5 \sec x - 4 = 06sec2x+5secx−4=0.

Hence, given x x\,x is obtuse find the exact value of tan⁡x\tan xtanx.

[5]
Markscheme

Trigonometric Functions Questions

  1. A Level
  2. /Maths
  3. /Trigonometric Functions

274 exam-style questions on Edexcel A Level Maths Trigonometric Functions, covering 6.1 Secant, Cosecant and Cotangent, 6.2 Graphs of Sec x, Cosec x and Cot x, 6.3 Using Sec x, Cosec x and Cot x, 6.4 Trigonometric Identities, and 6.5 Inverse Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.

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