Prove that cosθ+sinθtanθ≡secθ\cos \theta + \sin \theta \tan \theta \equiv \sec \thetacosθ+sinθtanθ≡secθ
Hence show that the equation cosθ+sinθtanθ=4cosθ\cos \theta + \sin \theta \tan \theta = 4 \cos \thetacosθ+sinθtanθ=4cosθ can be rearranged to give cos2θ=14\displaystyle \cos^2 \theta = \frac{1}{4}cos2θ=41
Hence find the exact roots of the equation cosθ+sinθtanθ=4cosθ\cos \theta + \sin \theta \tan \theta = 4 \cos \thetacosθ+sinθtanθ=4cosθ, for 0≤θ≤2π0 \leq \theta \leq 2\pi0≤θ≤2π
274 exam-style questions on Edexcel A Level Maths Trigonometric Functions, covering 6.1 Secant, Cosecant and Cotangent, 6.2 Graphs of Sec x, Cosec x and Cot x, 6.3 Using Sec x, Cosec x and Cot x, 6.4 Trigonometric Identities, and 6.5 Inverse Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.