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Trigonometric Functions

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Question 190

f(x)=2x3+3x2+7x+3f(x) = 2x^3 + 3x^2 + 7x + 3f(x)=2x3+3x2+7x+3

Prove that there are no real solutions to 2sec⁡2θ+3sec⁡θ+7+3cos⁡θ=02\sec^2 \theta + 3\sec \theta + 7 + 3\cos \theta = 02sec2θ+3secθ+7+3cosθ=0

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Trigonometric Functions Questions

  1. A Level
  2. /Maths
  3. /Trigonometric Functions

274 exam-style questions on Edexcel A Level Maths Trigonometric Functions, covering 6.1 Secant, Cosecant and Cotangent, 6.2 Graphs of Sec x, Cosec x and Cot x, 6.3 Using Sec x, Cosec x and Cot x, 6.4 Trigonometric Identities, and 6.5 Inverse Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.

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