The curve C C\,C has the equation y=(14−x)lnxx>0y = (14 - x) \ln x \quad x > 0y=(14−x)lnxx>0
Find dydx\displaystyle \frac{dy}{dx}dxdy
C C\,C has a stationary point at PPP. Show that the x x\,x coordinate of P P\,P lies between 5 and 5.5
Show that the x x\,x coordinate of P P\,P is a solution of x=141+lnx\displaystyle x = \frac{14}{1 + \ln x}x=1+lnx14
Use the iteration formula xn+1=141+lnxn\displaystyle x_{n+1} = \frac{14}{1 + \ln x_n}xn+1=1+lnxn14 with x0=5.25x_0 = 5.25x0=5.25 to find, to 3 decimal places, the values of x1,x2 x_1, x_2\,x1,x2 and x3x_3x3.
329 exam-style questions on Edexcel A Level Maths Numerical Methods, covering 10.1 Locating Roots, 10.2 Iteration, 10.3 The Newton-Raphson Method, and 10.4 Applications to Modelling. Each one has a worked solution and a mark scheme showing where the marks go.