f(x)=ln(2x+1)+x2−5x>−0.5f(x) = \ln(2x + 1) + x^2 - 5 \quad x > -0.5f(x)=ln(2x+1)+x2−5x>−0.5
Show that f(x)=0f(x) = 0f(x)=0 has a root in the interval [1.8,1.9][1.8, 1.9][1.8,1.9]
Find f′(x)f'(x)f′(x)
Using x0=kx_0 = kx0=k, where k>−0.5k > -0.5k>−0.5, as a first approximation, apply the Newton-Raphson procedure to find a second approximation, giving your answer in terms of kkk.
329 exam-style questions on Edexcel A Level Maths Numerical Methods, covering 10.1 Locating Roots, 10.2 Iteration, 10.3 The Newton-Raphson Method, and 10.4 Applications to Modelling. Each one has a worked solution and a mark scheme showing where the marks go.