f(x)=ln(4x+1)+x2−5x>−0.25f(x) = \ln(4x + 1) + x^2 - 5 \quad x > -0.25f(x)=ln(4x+1)+x2−5x>−0.25
Show that f(x)=0f(x) = 0f(x)=0 has a root in the interval [1.7,1.8][1.7, 1.8][1.7,1.8]
Find f′(x)f'(x)f′(x)
Using x0=1.7x_0 = 1.7x0=1.7 as a first approximation, apply the Newton-Raphson procedure to find a second approximation, giving your answer to 3 decimal places.
329 exam-style questions on Edexcel A Level Maths Numerical Methods, covering 10.1 Locating Roots, 10.2 Iteration, 10.3 The Newton-Raphson Method, and 10.4 Applications to Modelling. Each one has a worked solution and a mark scheme showing where the marks go.