A particle P P\,P moves with constant acceleration (2i−3j)(2\mathbf{i} - 3\mathbf{j})(2i−3j) m s−2^{-2}−2. When t=0t = 0t=0 the particle is at the point A A\,A and is moving with velocity (−3i+5j)(-3\mathbf{i} + 5\mathbf{j})(−3i+5j) m s−1^{-1}−1.
At time t=Tt = Tt=T seconds the particle is moving in the direction of the vector (3i−4j)(3\mathbf{i} - 4\mathbf{j})(3i−4j).
Find the value of TTT.
At time t=4t = 4t=4 seconds, P P\,P is at the point BBB. Find the distance ABABAB.
265 exam-style questions on AQA A Level Maths 3.2 Q: Kinematics, covering 3.2.1 Language of kinematics, 3.2.2 Graphs in kinematics, 3.2.3 Constant acceleration formulae, 3.2.4 Calculus in kinematics (A-level only), and 3.2.5 Motion under gravity and projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.