A particle moves in a straight line with constant acceleration aaa.
At time t=0t = 0t=0 the particle has velocity uuu. At time t t\,t the particle has velocity v v\,v and its displacement from its starting point is sss.
You may assume the results v=u+atv = u + atv=u+at and s=(u+v2)ts = \left(\dfrac{u + v}{2}\right)ts=(2u+v)t.
Derive the formula v2=u2+2asv^2 = u^2 + 2asv2=u2+2as.
Derive the formula s=ut+12at2\displaystyle s = ut + \frac12at^2s=ut+21at2.
265 exam-style questions on AQA A Level Maths 3.2 Q: Kinematics, covering 3.2.1 Language of kinematics, 3.2.2 Graphs in kinematics, 3.2.3 Constant acceleration formulae, 3.2.4 Calculus in kinematics (A-level only), and 3.2.5 Motion under gravity and projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.