A particle moves in a straight line so that at time t t\,t seconds, t≥0t \geq 0t≥0, its acceleration is a=(4t−8)a = (4t - 8)a=(4t−8) m s−2^{-2}−2
When t=0t = 0t=0 the velocity of the particle is 6 m s−1^{-1}−1.
Find v v\,v in terms of ttt.
Find the distance between the two points at which the particle is instantaneously at rest.
265 exam-style questions on AQA A Level Maths 3.2 Q: Kinematics, covering 3.2.1 Language of kinematics, 3.2.2 Graphs in kinematics, 3.2.3 Constant acceleration formulae, 3.2.4 Calculus in kinematics (A-level only), and 3.2.5 Motion under gravity and projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.