You may use the identity $sin⁡3x≡3sin⁡x−4sin⁡3x\sin 3x \equiv 3\sin x - 4\sin^3 x$ .

Solve, for $\leq x < \pi$ , the equation

$8\sin^3 x - 6\sin x + 1 = 0$

Give your answers in terms of $π\pi$ .

Hence write down the four solutions, in the interval $0≤y<π2\displaystyle 0 \leq y < \frac{\pi}{2}$ , of the equation

$8\sin^3 2y - 6\sin 2y + 1 = 0$

You may use the identity $sin⁡3x≡3sin⁡x−4sin⁡3x\sin 3x \equiv 3\sin x - 4\sin^3 x$ .

Solve, for $\leq x < \pi$ , the equation

$8\sin^3 x - 6\sin x + 1 = 0$

Give your answers in terms of $π\pi$ .

Hence write down the four solutions, in the interval $0≤y<π2\displaystyle 0 \leq y < \frac{\pi}{2}$ , of the equation

$8\sin^3 2y - 6\sin 2y + 1 = 0$

1 Pure Mathematics

1 Pure Mathematics Questions