Identify the expression that 1−cos2θsinθ\dfrac{1 - \cos^2\theta}{\sin\theta}sinθ1−cos2θ simplifies to, where sinθ≠0\sin\theta \neq 0sinθ=0.
Circle your answer.
cosθ\cos\thetacosθ
sinθ\sin\thetasinθ
tanθ\tan\thetatanθ
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