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Question 116

A social media rumor is spreading through a university campus of 2500 students. Initially, 50 students have heard the rumor. The number of students who have heard the rumor is observed to increase by 40% each hour.

a.

The total number of students who have heard the rumor, xxx, is modelled by

x=A×Bt x = A \times B^t x=A×Bt

where A A\,A and B B\,B are constants and t t\,t is the number of hours after the rumor first started.

(i) Based on this model, calculate the number of students who have heard the rumor 5 hours after it started.

[2]
b.

(ii) Explain why this model is not appropriate for predicting the spread of the rumor over a long period of time.

[1]
c.

A more sophisticated model assumes that the rate at which the rumor spreads is given by the differential equation

dxdt=x(2500−x)5000 \frac{dx}{dt} = \frac{x(2500 - x)}{5000} dtdx​=5000x(2500−x)​

(i) Show that

∫(Cx+D2500−x)dx=∫dt \int \left( \frac{C}{x} + \frac{D}{2500 - x} \right) dx = \int dt ∫(xC​+2500−xD​)dx=∫dt

where C C\,C and D D\,D are positive integers to be found.

[3]
d.

(ii) Hence, find t t\,t in terms of xxx.

[3]
e.

(iii) Calculate the number of hours it takes for half of the student population to have heard the rumor.

[2]

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