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1 Pure Mathematics

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Question 201

A scientist monitoring the growth of a synthetic crystal determines that the rate of change of its mass, MMM in milligrams, with respect to time ttt in hours, is given by:

dMdt=5t4−3t34,t>0 \frac{dM}{dt} = 5t^4 - \frac{3}{\sqrt[4]{t^3}}, \quad t > 0 dtdM​=5t4−4t3​3​,t>0

Determine the general expression for the mass M(t)M(t)M(t).

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