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1 Pure Mathematics

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Question 1352

A series of robotic pulses is programmed such that the energy, EkE_kEk​, of the kkk-th pulse follows a geometric sequence with first term aaa Joules and common ratio rrr, where r>0r > 0r>0.

Given that

  • the 2nd pulse has energy 108108108 Joules
  • the 4th pulse has energy 484848 Joules
a.

Show that r=23r = \frac{2}{3}r=32​.

[2]
b.

Determine the value of aaa.

[1]
c.

Given that the total energy released by the first nnn pulses is greater than 480480480 Joules,

find the smallest possible value of nnn.

(Solutions based entirely on graphical or numerical methods are not acceptable.)

[4]

1 Pure Mathematics Questions

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