Which equation does not show the reduction of a transition metal?
TiCl4+4Na→Ti+4NaCl\text{TiCl}_4 + 4\text{Na} \rightarrow \text{Ti} + 4\text{NaCl}TiCl4+4Na→Ti+4NaCl
2Cu2++4I−→2CuI+I22\text{Cu}^{2+} + 4\text{I}^- \rightarrow 2\text{CuI} + \text{I}_22Cu2++4I−→2CuI+I2
Cr2O72−+14H++6Cl−→2Cr3++3Cl2+7H2O\text{Cr}_2\text{O}_7^{2-} + 14\text{H}^+ + 6\text{Cl}^- \rightarrow 2\text{Cr}^{3+} + 3\text{Cl}_2 + 7\text{H}_2\text{O}Cr2O72−+14H++6Cl−→2Cr3++3Cl2+7H2O
[Cu(H2O)6]2++4Cl−→[CuCl4]2−+6H2O[\text{Cu}(\text{H}_2\text{O})_6]^{2+} + 4\text{Cl}^- \rightarrow [\text{CuCl}_4]^{2-} + 6\text{H}_2\text{O}[Cu(H2O)6]2++4Cl−→[CuCl4]2−+6H2O
