Upper and Lower Bounds Using Error Intervals
Learn how to find lower and upper bounds from rounded values, write correct error intervals, and avoid common GCSE Maths exam mistakes with examples.
📋 Spec coverage: GCSE Edexcel Mathematics (1MA1) This article covers:
- Edexcel N15 - Rounding and error intervals: using inequality notation to give error intervals for rounded values.
- Edexcel N16 - Limits of accuracy: identifying and interpreting upper and lower bounds.
Tier: Foundation and Higher. These skills can be assessed on Papers 1, 2 or 3.
To find the lower and upper bounds, take half of the rounding unit. Subtract it from the rounded value for the lower bound and add it for the upper bound.
Lower bound=rounded value−rounding unit2\text{Lower bound}=\text{rounded value}-\frac{\text{rounding unit}}{2}Lower bound=rounded value−2rounding unit Upper bound=rounded value+rounding unit2\text{Upper bound}=\text{rounded value}+\frac{\text{rounding unit}}{2}Upper bound=rounded value+2rounding unitThis assumes the value was rounded normally rather than truncated.
Writing an error interval
An error interval shows every possible original value. If the lower bound is LLL, the upper bound is UUU, and the original value is xxx, write:
L≤x<UL\le x<UL≤x<UThe lower bound is included, but the upper bound is not. This is because a value exactly equal to the upper bound would round up to the next number.
Worked example
A length is 7.4 cm7.4\text{ cm}7.4 cm, correct to the nearest 0.1 cm0.1\text{ cm}0.1 cm.
Half of the rounding unit is:
0.1÷2=0.050.1\div 2=0.050.1÷2=0.05Therefore:
Lower bound=7.4−0.05=7.35\text{Lower bound}=7.4-0.05=7.35Lower bound=7.4−0.05=7.35 Upper bound=7.4+0.05=7.45\text{Upper bound}=7.4+0.05=7.45Upper bound=7.4+0.05=7.45The error interval is:
7.35≤x<7.457.35\le x<7.457.35≤x<7.45So the lower bound is 7.35 cm7.35\text{ cm}7.35 cm and the upper bound is 7.45 cm7.45\text{ cm}7.45 cm.
Quick second example
A mass is 320 g320\text{ g}320 g, rounded to the nearest 10 g10\text{ g}10 g. The rounding unit is 10 g10\text{ g}10 g, so half is 5 g5\text{ g}5 g. The possible values run from 315 g315\text{ g}315 g up to, but not including, 325 g325\text{ g}325 g:
315≤x<325315\le x<325315≤x<325Notice that the displayed value does not have to be a decimal. The same half-unit method works for whole numbers, decimal places and measurements.
Common exam mistake
Do not write x≤7.45x\le 7.45x≤7.45. The upper bound is not included, so you need the strict inequality x<7.45x<7.45x<7.45.
Also check the rounding unit carefully. For example, rounding to the nearest 101010 gives a half-unit of 555, not 0.50.50.5.
Completeness check: This covers finding both bounds, writing the error interval with correct inequality notation, and interpreting which endpoints are included.