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Alkenes

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Question 14

The table below lists six organic compounds, labeled P to U, and shows their structures or formulas:

LetterCompound Name / Structure
PEthane, CH3CH3\text{CH}_3\text{CH}_3CH3​CH3​
QPropene, CH3CH=CH2\text{CH}_3\text{CH}=\text{CH}_2CH3​CH=CH2​
RPropane, CH3CH2CH3\text{CH}_3\text{CH}_2\text{CH}_3CH3​CH2​CH3​
SPent-2-ene, CH3CH=CHCH2CH3\text{CH}_3\text{CH}=\text{CHCH}_2\text{CH}_3CH3​CH=CHCH2​CH3​
TCyclopentane, a cyclic molecule containing a ring of five CH2\text{CH}_2CH2​ groups
UHexane, CH3CH2CH2CH2CH2CH3\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_3CH3​CH2​CH2​CH2​CH2​CH3​
a.

Explain why all of these compounds are described as hydrocarbons.

[1]
b.

Why are Q and S described as unsaturated?

[1]
c.

Which letter represents the member of the homologous series of alkanes with two carbon atoms?

[1]
d.

Which letters represent compounds that have the empirical formula CH2\text{CH}_2CH2​?

[1]
e.

Compound T has the same general formula as an alkene. Why does T not decolourise bromine water?

[1]
f.

One of the compounds in the table reacts with bromine to form H, a compound with the percentage composition by mass: C=29.5%\text{C} = 29.5\%C=29.5%, H=4.9%\text{H} = 4.9\%H=4.9%, Br=65.6%\text{Br} = 65.6\%Br=65.6%. (Relative atomic masses: C=12\text{C} = 12C=12, H=1\text{H} = 1H=1, Br=80\text{Br} = 80Br=80)

Show, by calculation, that the empirical formula of H is C3H6Br\text{C}_3\text{H}_6\text{Br}C3​H6​Br.

[3]
g.

The relative formula mass of H is 244. Deduce the molecular formula of H.

[2]

Alkenes Questions

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