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Alkenes

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Question 1

The table below lists six organic compounds, labeled J to O, and shows their structures or formulas:

LetterCompound Name / Structure
JButane, CH3CH2CH2CH3\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_3CH3​CH2​CH2​CH3​
KBut-2-ene, CH3CH=CHCH3\text{CH}_3\text{CH}=\text{CHCH}_3CH3​CH=CHCH3​
LCyclohexane, a cyclic molecule containing a ring of six CH2\text{CH}_2CH2​ groups
MPent-1-ene, CH2=CHCH2CH2CH3\text{CH}_2=\text{CHCH}_2\text{CH}_2\text{CH}_3CH2​=CHCH2​CH2​CH3​
NMethane, CH4\text{CH}_4CH4​
OOctane, CH3CH2CH2CH2CH2CH2CH2CH3\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_2\text{CH}_3CH3​CH2​CH2​CH2​CH2​CH2​CH2​CH3​
a.

Explain why all of these compounds are described as hydrocarbons.

[1]
b.

Why are K and M described as unsaturated?

[1]
c.

Which letter represents the member of the homologous series of alkanes with four carbon atoms?

[1]
d.

Which letters represent compounds that have the empirical formula CH2\text{CH}_2CH2​?

[1]
e.

Compound L has the same general formula as an alkene. Why does L not decolourise bromine water?

[1]
f.

One of the compounds in the table reacts with bromine to form G, a compound with the percentage composition by mass: C=22.2%\text{C} = 22.2\%C=22.2%, H=3.7%\text{H} = 3.7\%H=3.7%, Br=74.1%\text{Br} = 74.1\%Br=74.1%. (Relative atomic masses: C=12\text{C} = 12C=12, H=1\text{H} = 1H=1, Br=80\text{Br} = 80Br=80)

Show, by calculation, that the empirical formula of G is C2H4Br\text{C}_2\text{H}_4\text{Br}C2​H4​Br.

[3]
g.

The relative formula mass of G is 216. Deduce the molecular formula of G.

[2]

Alkenes Questions

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