An explorer standing in a wide canyon lets out a loud shout.
After a short delay, they hear an echo of their shout.
Explain why they hear this second sound and why it is quieter than the original shout.
The time between the shout and hearing the echo is 1.60 s1.60\text{ s}1.60 s. The speed of sound in the canyon air is 320 m/s320\text{ m/s}320 m/s. Calculate the distance from the explorer to the canyon wall.
The explorer then sings two different steady notes: Tone X and Tone Y.
Explain how the wavelength of Tone X compares to the wavelength of Tone Y.