Question 4
FThe Figure shows a circuit with two resistors connected in parallel to a 6.0 V battery.
Figure
a.[1]
State the potential difference across the 12 Ω resistor.
b.[2]
Use the equation: potential difference=current×resistance\text{potential difference} = \text{current} \times \text{resistance}potential difference=current×resistance
Calculate the reading on ammeter A2.
c.[1]
The reading on ammeter A3 is 1.0 A.
Calculate the reading on ammeter A1.
d.[2]
Calculate the total resistance of the circuit.
e.[2]
The total resistance of the circuit is less than the resistance of either resistor.
Explain why.
3.2 Simple circuits Questions
42 exam-style questions on OCR GCSE Physics 3.2 Simple circuits, covering 3.2.1 Series and parallel circuits, 3.2.2 Circuit symbols and circuit diagrams, 3.2.3 Current, potential difference and resistance, 3.2.4 Ohm's law, 3.2.5 Ohmic and non-ohmic resistors, 3.2.6 Designing circuits to investigate resistance, 3.2.7 Linear and non-linear circuit components, 3.2.8 Current-potential difference graphs for components, 3.2.9 Resistance in series and parallel, 3.2.10 Series and parallel circuit problems, 3.2.11 Circuits for measurement and testing, 3.2.12 Power transfer in circuit devices, and 3.2.13 Energy and power in resistor circuits. Each one has a worked solution and a mark scheme showing where the marks go.