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Question 15

Show that the equation $x^3 + 4x = k$ , where $0 < k < 5$ , has a solution between $x = 0$ and $x = 1$ .

[2]

Show that the equation $x^3 + 4x = k$ can be rearranged to give: $x=k4−x34\displaystyle x = \frac{k}{4} - \frac{x^3}{4}$

[1]

Starting with $x_0 = 0$ , use the iteration formula $xn+1=k4−xn34\displaystyle x_{n+1} = \frac{k}{4} - \frac{x_n^3}{4}$ twice to find an estimate for the solution to $x^3 + 4x = k$

[3]

Markscheme

Iteration Questions

GCSE
Maths
Iteration

124 exam-style questions on OCR GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.

Iteration

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Question 15

Show that the equation $x^3 + 4x = k$ , where $0 < k < 5$ , has a solution between $x = 0$ and $x = 1$ .

[2]

Show that the equation $x^3 + 4x = k$ can be rearranged to give: $x=k4−x34\displaystyle x = \frac{k}{4} - \frac{x^3}{4}$

[1]

Starting with $x_0 = 0$ , use the iteration formula $xn+1=k4−xn34\displaystyle x_{n+1} = \frac{k}{4} - \frac{x_n^3}{4}$ twice to find an estimate for the solution to $x^3 + 4x = k$

[3]

Markscheme

Iteration Questions

GCSE
Maths
Iteration

124 exam-style questions on OCR GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.