Show that the equation 7x3+2x2−36=07x^3 + 2x^2 - 36 = 07x3+2x2−36=0 has a solution between x=1x = 1x=1 and x=2x = 2x=2.
Show that the equation 7x3+2x2−36=07x^3 + 2x^2 - 36 = 07x3+2x2−36=0 can be rearranged to give: x=367x+2\displaystyle x = \sqrt{\frac{36}{7x + 2}}x=7x+236
Starting with x0=1x_0 = 1x0=1, use the iteration formula xn+1=367xn+2\displaystyle x_{n+1} = \sqrt{\frac{36}{7x_n + 2}}xn+1=7xn+236 twice to find an estimate for the solution to 7x3+2x2−36=07x^3 + 2x^2 - 36 = 07x3+2x2−36=0
124 exam-style questions on OCR GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.