Show that the equation 17x3+15x2−72=017x^3 + 15x^2 - 72 = 017x3+15x2−72=0 has a solution between x=1x = 1x=1 and x=2x = 2x=2.
Show that the equation 17x3+15x2−72=017x^3 + 15x^2 - 72 = 017x3+15x2−72=0 can be rearranged to give: x=7217x+15\displaystyle x = \sqrt{\frac{72}{17x + 15}}x=17x+1572
Starting with x0=1x_0 = 1x0=1, use the iteration formula xn+1=7217xn+15\displaystyle x_{n+1} = \sqrt{\frac{72}{17x_n + 15}}xn+1=17xn+1572 twice to find an estimate for the solution to 17x3+15x2−72=017x^3 + 15x^2 - 72 = 017x3+15x2−72=0
124 exam-style questions on OCR GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.