Show that the equation x3+4x=2x^3 + 4x = 2x3+4x=2 has a solution between x=0x = 0x=0 and x=1x = 1x=1.
Show that the equation x3+4x=2x^3 + 4x = 2x3+4x=2 can be rearranged to give: x=12−x34\displaystyle x = \frac{1}{2} - \frac{x^3}{4}x=21−4x3
Starting with x0=0x_0 = 0x0=0, use the iteration formula xn+1=12−xn34\displaystyle x_{n+1} = \frac{1}{2} - \frac{x_n^3}{4}xn+1=21−4xn3 twice to find an estimate for the solution to x3+4x=2x^3 + 4x = 2x3+4x=2
124 exam-style questions on Eduqas GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.