Using xn+1=1+4xn2\displaystyle x_{n+1} = 1 + \frac{4}{x_n^2}xn+1=1+xn24 with x0=2x_0 = 2x0=2
Explain the relationship between the values of x1x_1x1, x2 x_2\,x2 and x3 x_3\,x3 and the equation x3−x2−4=0x^3 - x^2 - 4 = 0x3−x2−4=0
124 exam-style questions on Eduqas GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.