Show that the equation 16x3−7x2−36=016x^3 - 7x^2 - 36 = 016x3−7x2−36=0 has a solution between x=1x = 1x=1 and x=2x = 2x=2.
Show that the equation 16x3−7x2−36=016x^3 - 7x^2 - 36 = 016x3−7x2−36=0 can be rearranged to give: x=3616x−7\displaystyle x = \sqrt{\frac{36}{16x - 7}}x=16x−736
Starting with x0=1x_0 = 1x0=1, use the iteration formula xn+1=3616xn−7\displaystyle x_{n+1} = \sqrt{\frac{36}{16x_n - 7}}xn+1=16xn−736 twice to find an estimate for the solution to 16x3−7x2−36=016x^3 - 7x^2 - 36 = 016x3−7x2−36=0
124 exam-style questions on Eduqas GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.