A hydrogen-oxygen fuel cell with an acidic electrolyte produces electricity.
Hydrogen reacts with oxygen to produce water.
What is the equation for the reaction that happens at the cathode?
2H2(g)+O2(g)→2H2O(g)2\text{H}_2(\text{g}) + \text{O}_2(\text{g}) \rightarrow 2\text{H}_2\text{O}(\text{g})2H2(g)+O2(g)→2H2O(g)
2H2(g)→4H+(aq)+4e−2\text{H}_2(\text{g}) \rightarrow 4\text{H}^+(\text{aq}) + 4\text{e}^-2H2(g)→4H+(aq)+4e−
O2(g)+4H+(aq)+4e−→2H2O(g)\text{O}_2(\text{g}) + 4\text{H}^+(\text{aq}) + 4\text{e}^- \rightarrow 2\text{H}_2\text{O}(\text{g})O2(g)+4H+(aq)+4e−→2H2O(g)
4H+(aq)+4e−→2H2(g)4\text{H}^+(\text{aq}) + 4\text{e}^- \rightarrow 2\text{H}_2(\text{g})4H+(aq)+4e−→2H2(g)