Propanoic acid and butanoic acid are both members of the same homologous series as ethanoic acid.
HHO∣∣ / /H−C−C−C−O−H∣∣HH \begin{array}{lccccc} & \text{H} & \text{H} & \text{O} & & \\ & | & | & \!\!/\!/ & & \\ \text{H} & -\text{C} & -\text{C} & -\text{C} & -\text{O} & -\text{H} \\ & | & | & & & \\ & \text{H} & \text{H} & & & \end{array} HH∣−C∣HH∣−C∣HO//−C−O−Hpropanoic acid
HHHO∣∣∣ / /H−C−C−C−C−O−H∣∣∣HHH \begin{array}{lcccccc} & \text{H} & \text{H} & \text{H} & \text{O} & & \\ & | & | & | & \!\!/\!/ & & \\ \text{H} & -\text{C} & -\text{C} & -\text{C} & -\text{C} & -\text{O} & -\text{H} \\ & | & | & | & & & \\ & \text{H} & \text{H} & \text{H} & & & \end{array} HH∣−C∣HH∣−C∣HH∣−C∣HO//−C−O−Hbutanoic acid
Give three reasons why ethanoic acid, propanoic acid and butanoic acid are members of the same homologous series.
Practise Edexcel GCSE Chemistry Alcohols and carboxylic acids with exam-style questions for Foundation and Higher tier. 55 questions, matched to the Edexcel GCSE Chemistry (1CH0) specification and written in Paper 1 and Paper 2 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.
