Yield and atom economy of chemical reactions (chemistry only)

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Question 6
Easy

Copper is extracted from copper(I) sulfide by heating it in a stream of oxygen gas. The equation for the reaction is:

Cu2S+O2→2Cu+SO2 \text{Cu}_2\text{S} + \text{O}_2 \rightarrow 2\text{Cu} + \text{SO}_2 Cu2​S+O2​→2Cu+SO2​

Calculate the percentage atom economy for obtaining copper from this reaction.

Use the equation:

Percentage atom economy=2×Ar of CuMr of Cu2S+Mr of O2×100 \text{Percentage atom economy} = \frac{2 \times A_{\text{r}}\text{ of Cu}}{M_{\text{r}}\text{ of Cu}_2\text{S} + M_{\text{r}}\text{ of O}_2} \times 100 Percentage atom economy=Mr​ of Cu2​S+Mr​ of O2​2×Ar​ of Cu​×100

Relative atomic masses (ArA_{\text{r}}Ar​): Cu=63.5\text{Cu} = 63.5Cu=63.5. Relative formula masses (MrM_{\text{r}}Mr​): Cu2S=159\text{Cu}_2\text{S} = 159Cu2​S=159, O2=32\text{O}_2 = 32O2​=32.

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Yield and atom economy of chemical reactions (chemistry only) Questions

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