Yield and atom economy of chemical reactions (chemistry only)

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Question 3
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This question is about the extraction of metals.

Element Y is extracted from its oxide by reduction with carbon. The equation for the reaction is:

YO2+C→Y+CO2 \text{YO}_2 + \text{C} \rightarrow \text{Y} + \text{CO}_2 YO2​+C→Y+CO2​
a.

The sum of the relative formula masses (MrM_rMr​) of the reactants (YO2+C\text{YO}_2 + \text{C}YO2​+C) is 99. Calculate the relative atomic mass (ArA_rAr​) of Y. Relative atomic masses (ArA_rAr​): C=12\text{C} = 12C=12, O=16\text{O} = 16O=16

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b.

Identify element Y using your answer to Part 1 and a periodic table.

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c.

Carbon can also be used to extract iron (Fe\text{Fe}Fe) from iron(III) oxide (Fe2O3\text{Fe}_2\text{O}_3Fe2​O3​). The equation for the overall reaction is:

Fe2O3+3C→2Fe+3CO \text{Fe}_2\text{O}_3 + 3\text{C} \rightarrow 2\text{Fe} + 3\text{CO} Fe2​O3​+3C→2Fe+3CO

Calculate the percentage atom economy for extracting iron in this reaction. Give your answer to 2 significant figures. Relative atomic masses (ArA_rAr​): C=12\text{C} = 12C=12, O=16\text{O} = 16O=16, Fe=56\text{Fe} = 56Fe=56

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Yield and atom economy of chemical reactions (chemistry only) Questions

  1. GCSE
  2. /Chemistry
  3. /Yield and atom economy of chemical reactions (chemistry only)