A student uses a light microscope with a total magnification of ×100\times 100×100. The diameter of the field of view is 0.50 mm.
The student changes the total magnification to ×400\times 400×400. Five cells fit end to end across the diameter of the new field of view.
What is the best estimate of the length of one cell?
2.5 μm2.5\ \mu\text{m}2.5 μm
25 μm25\ \mu\text{m}25 μm
100 μm100\ \mu\text{m}100 μm
400 μm400\ \mu\text{m}400 μm
130 exam-style questions on OCR GCSE Biology 1.1 Cell structures, covering 1.1.1 Viewing cells with light microscopes, 1.1.2 Sub-cellular structures and functions, and 1.1.3 Electron microscopy and resolution. Each one has a worked solution and a mark scheme showing where the marks go.