Common Mistakes with Iteration in GCSE Maths
Common mistakes with iteration in GCSE maths explained through worked examples. Fix subscripts, calculator entries and rounding with clear practice tips.

An iteration answer can look convincing while containing one small error that changes every value afterwards. The common mistakes with iteration in GCSE maths usually involve misreading the subscripts, entering the formula incorrectly, rounding too early or stopping before answering the question. You can fix them by treating each calculation as a careful handover: the latest output becomes the next input.
Imagine a student checking an unsuccessful attempt. They understand that iteration means repeating something, but their working keeps returning the wrong answer. Following their corrections reveals where the marks can be lost, and how to make the method reliable.
Your iteration checklist
Before calculating, check that you can identify:
- The starting value supplied in the question.
- The formula that generates the next value.
- Which iterate you must calculate.
- Any requested accuracy or stopping condition.
- The working you need to show.
Iteration is a Higher tier GCSE topic. If the notation feels unfamiliar, the MathsGenie iteration lesson explains the process from the beginning.
Common mistakes with iteration in GCSE maths
Mistaking a subscript for an operation
Our hypothetical student sees:
xn+1=xn+6,x0=2x_{n+1}=\sqrt{x_n+6},\qquad x_0=2xn+1=xn+6,x0=2They read xn+1x_{n+1}xn+1 as “add one to xnx_nxn”. That feels plausible because the notation contains a plus sign, but the subscript labels a position in the sequence.
Here, xnx_nxn is the current value and xn+1x_{n+1}xn+1 is the next value. The formula tells you how to move between them.
Starting with x0=2x_0=2x0=2:
x1=x0+6=2+6=8x_1=\sqrt{x_0+6}=\sqrt{2+6}=\sqrt{8}x1=x0+6=2+6=8Therefore:
x1≈2.828427x_1\approx2.828427x1≈2.828427The correction: read the formula aloud as “the next value equals the square root of the current value plus six”. Keep the whole expression inside the square root.
Reusing the starting value
The student now calculates the first value correctly, but substitutes 222 again for the second calculation. Their answer repeats because they have repeated the same input.
The starting value starts the process. After that, each new answer takes its place:
x2=x1+6x_2=\sqrt{x_1+6}x2=x1+6Using the unrounded value of x1x_1x1 gives:
x2≈2.971267x_2\approx2.971267x2≈2.971267A short table helps you track the handover:
| Position | Value shown to six decimal places |
|---|---|
| x0x_0x0 | 2.0000002.0000002.000000 |
| x1x_1x1 | 2.8284272.8284272.828427 |
| x2x_2x2 | 2.9712672.9712672.971267 |
| x3x_3x3 | 2.9952072.9952072.995207 |
| x4x_4x4 | 2.9992012.9992012.999201 |
These displayed values are rounded for readability. Keep the full calculator value between steps.
The correction: after every calculation, ask, “Which value is my next input?”
Entering a different formula on the calculator
The student understands the handover, but their calculator entry places the addition outside the square root:
xn+6\sqrt{x_n}+6xn+6That is a different rule from:
xn+6\sqrt{x_n+6}xn+6This mistake happens when attention shifts from the written formula to the calculator buttons. Fraction bars, powers and square roots all group expressions, and your entry must preserve those groups.
The correction: check that the square-root template covers the entire expression xn+6x_n+6xn+6. If you use the calculator's previous-answer function, confirm that it currently contains the intended input. An unrelated calculation can replace it.
Once you have the input, formula and handover clear, use MathsGenie's iteration Lessons and Question Bank to practise that same routine with further questions.
Rounding every answer before continuing
The next temptation is to shorten every answer. The student writes x1=2.83x_1=2.83x1=2.83 and then types that rounded value into the next calculation.
It saves a little writing, but changes the input. Repeated rounding can affect later values, especially when the question requires greater accuracy.
The correction: separate what you display from what you calculate with. You can record a suitably rounded value on paper while retaining the full value in your calculator.
Follow any explicit instructions about rounding. Otherwise, retain full precision during the process and round the requested answer at the end. The MathsGenie rounding lesson can help if decimal places and significant figures are causing a separate difficulty.
Counting the starting value as the first iteration
The student is asked for x3x_3x3, but stops after calculating x2x_2x2. They have counted the supplied starting value as their first calculation.
When the question gives x0x_0x0, it is the starting position. Applying the formula once produces x1x_1x1, twice produces x2x_2x2, and three times produces x3x_3x3.
The correction: label each line before entering the numbers. Writing x1x_1x1, x2x_2x2 and x3x_3x3 down the page makes the destination visible.
Read the question carefully because a sequence can use a different starting label. Follow the notation supplied rather than assuming every question begins with x0x_0x0.
Rearranging the equation incorrectly
Some questions ask you to show how an equation leads to an iteration formula. The student recognises the expected square root and jumps straight to it, dropping a term along the way.
For example, starting from:
x2−x−6=0x^2-x-6=0x2−x−6=0add x+6x+6x+6 to both sides:
x2=x+6x^2=x+6x2=x+6For the positive-root iteration used here, this gives:
x=x+6x=\sqrt{x+6}x=x+6The corresponding iterative rule is:
xn+1=xn+6x_{n+1}=\sqrt{x_n+6}xn+1=xn+6The correction: show the algebra before introducing the subscripts. The original equation also has a negative root; this positive-square-root rule targets the positive one. When a question supplies an iteration formula, use that formula as instructed.
The AQA iteration revision guide provides another explanation of the notation and process.
Stopping without answering the question
Finally, the student's values look close together, so they stop. But “close together” does not automatically satisfy the instruction.
If asked for x3x_3x3, calculate and identify x3x_3x3. If asked for a root to a stated accuracy, continue sufficiently far to support that rounded answer. When asked to justify accuracy using a sign change, substitute suitable bounding values into the original expression and show opposite signs.
The correction: finish by rereading the command. A fixed number of iterations, an approximate root and a justification of accuracy are different tasks.
Repeated values can suggest convergence, but do not assume every iteration formula converges from every starting value.
Exam-style practice: check the whole routine
Use the rule:
xn+1=xn+6,x0=0x_{n+1}=\sqrt{x_n+6},\qquad x_0=0xn+1=xn+6,x0=0Calculate x1x_1x1 and x2x_2x2, giving both answers to four decimal places. Keep the full first value when calculating the second.
Try it before reading the working.
First substitution:
x1=0+6=6≈2.4495x_1=\sqrt{0+6}=\sqrt{6}\approx2.4495x1=0+6=6≈2.4495Second substitution:
x2=6+6≈2.9068x_2=\sqrt{\sqrt{6}+6}\approx2.9068x2=6+6≈2.9068Check more than the final numbers. Did you use the new value, keep the addition inside the root, retain precision and label both answers? Those habits transfer to unfamiliar formulas. For further independent practice, use the iteration exam booklet.
Turn the corrections into a reliable method
The student's working becomes dependable once each line has a labelled input, a checked substitution and a clear destination. Your next step is to repeat that routine until you can spot your own errors without prompting. Start with the iteration Lesson, then apply the corrections in the iteration Question Bank.



